Nicholas Clark is in town, this calls for an emergency social! Join us tomorrow at The Kernel Tap Room.
Emergency SocialStarts: Thursday August 21, 2025 @ 6:00 PM GMT+01:00 (Europe/London)Finishes: Thursday August 21, 2025 @ 10:30 PM GMT+01:00 (Europe/London)Nicholas Clark is in town, this calls for drinks!Location: The Kernel Brewery Tap RoomArch 7 Spa RoadBermondsey SE1 6 3AE
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I was using my $tmp = glob("file20240101.*") to find the full filename regardless of the extension(I knew there was only one of each file), when I found glob was alternating between working and failing
Rendering it as my ($tmp) = glob("file20240101.*") fixed the problem, but I'm wondering why, If it was going to go wrong I'd have thought treating glob's list in a scalar context would return the number of elements in the list
#!/usr/bin/perl
use warnings;
use strict;
for (1..4) {
my $tmp = glob($0);
print "$_ $tmp\n";
}
print "###\n";
for (1..4) {
my ($tmp) = glob($0);
print "$_ $tmp\n";
}
Output:
1 glob.pl
Use of uninitialized value $tmp in concatenation (.) or string at glob.pl line 7.
2
3 glob.pl
Use of uninitialized value $tmp in concatenation (.) or string at glob.pl line 7.
4
###
1 glob.pl
2 glob.pl
3 glob.pl
4 glob.pl
submitted by /u/octobod
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Hi,
I don't get why this produces a syntax error:
my %r = map { "a$_" => 1 } qw(q w);
yet this works:
my %r = map { "a" . $_ => 1 } qw(q w);
What is going on here?
submitted by /u/ghiste
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Let me explain my goal.
Let's say I have a file with a set of paths to files:
/usr/lib32/libssl.so
/usr/lib32/libz.so
...
and so on.
What's an easy way in perl to turn that input into:
/usr/lib32/libssl.so /usr/lib32/libssl.so
/usr/lib32/libz.so /usr/lib32/libz.so
...
Basically duplicate every string to the same line, delimited by a space?
Thanks for any assistance. I use perl's regex regularly for substitutions and the like (instead of using sed) and I prefer PCRE to sed. That said, not familiar with a way to do this.
submitted by /u/ShiningRaion
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